We consider the routing open shop, being a generalization of two well-known discrete optimization problems, namely open shop and metric traveling salesman problem. Immovable jobs are located at the nodes of the transportation network, and mobile machines have to tra- verse the network, sequentially performing operations on the jobs. Each job has to be processed by each machine in arbitrary order, processing times are known in advance. The machines are initially located at the predefined depot and have to return there after processing the jobs. The goal is to construct a feasible schedule with minimal makespan. The problem is known to be NP-hard even for the simplest case with two machines and two nodes. Moreover, it remains NP-hard in the special proportionate case, when processing times do not depend on machine. We propose a new special case for scheduling problems with proportional processing times or rank P = 1, where P is the matrix of processing times. We investigate the two-machine routing open shop with at most three nodes of transportation network in terms of proportionality factor k of rows of P and present the following results:
1. the problem instance is normal (i.e. its optimal makespan coincides with the standard lower bound ¯R) if and only if k ≥ Φ, where Φ is the golden ratio;
2. for any k ∈ [1, Φ] the optimal makespan does not exceed f(k) = (4k^2+3k)/(5k^2+2k−1) ¯R;
3. an optimal schedule in case k ≥ Φ and a feasible schedule with makespan at most f(k) ¯R can be constructed in linear time.
Therefore, we describe a new polynomially solvable case (k ≥ Φ) and a linear approximation algorithm for which the worst performance ratio guarantee is as small as theoretically possible in terms of the standard lower bound.